generalized momentum造句
例句与造句
- Using the definition of generalized momentum and Lagrange's equation for the coordinate:
- and integrating shows the corresponding generalized momentum equals a constant, a conserved quantity.
- where again the generalized velocity is to be expressed as a function of generalized momentum via its defining relation.
- where the definition of generalized momentum and Euler Lagrange equations have replaced the partial derivatives of " L ".
- where the second equation is the definition of the generalized momentum corresponding to the coordinate ( partial derivatives are denoted using ).
- It's difficult to find generalized momentum in a sentence. 用generalized momentum造句挺难的
- The " generalized momentum " " canonically conjugate to " the coordinate " q i " is defined by
- Hamiltonian mechanics aims to replace the generalized velocity variables with generalized momentum variables, also known as " conjugate momenta ".
- The definition of a generalized momentum can be retained, and the advantageous connection between cyclic coordinates and conserved quantities will continue to apply.
- In Cartesian coordinates, the generalized momenta are precisely the physical linear circular polar coordinates, the generalized momentum corresponding to the angular velocity is the physical angular momentum.
- The " kinetic momentum " is different from the " canonical momentum " ( synonymous with the generalized momentum ) conjugate to the ordinary position coordinates, because includes a contribution from the electric potential and vector potential:
- As in Hamiltonian mechanics where every generalized coordinate has a corresponding generalized momentum, the field has a "'conjugate momentum field "', defined as the partial derivative of the Lagrangian density with respect to the time derivative of the field,
- If the Lagrangian " L " does " not " depend on some coordinate " q i ", then it follows from the Euler Lagrange equations that the corresponding generalized momentum will be a conserved quantity, because the time derivative is zero implying the momentum is a constant of the motion;
- The units and nature of each generalized momentum will depend on the corresponding coordinate; in this case " p z " is a translational momentum in the " z " direction, " p s " is also a translational momentum along the curve " s " is measured, and " p ? " is an angular momentum in the plane the angle " ? " is measured in.
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